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− 2/sqr3 cos 3θ = 1 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! An equation is given. (Enter your answers as a comma-separated list. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
− 2/sqr3 cos 3θ = 1
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[0,2π]
cos 3θ=1/(-2/√3)=-√3/2
3θ=7π/6 and 11π/6 in quadrants III and IV where cos<0
θ=7π/18 and 11π/18
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