SOLUTION: Kristina needs to mix a 30% methanol solution with a 60% methanol solution to create 200 millileters of a 49.5% solution. How many millileters of each solution must Kristina use?
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-> SOLUTION: Kristina needs to mix a 30% methanol solution with a 60% methanol solution to create 200 millileters of a 49.5% solution. How many millileters of each solution must Kristina use?
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Question 670954: Kristina needs to mix a 30% methanol solution with a 60% methanol solution to create 200 millileters of a 49.5% solution. How many millileters of each solution must Kristina use?
Answer: Kristina must mix
millileters of 30% solution and ________________
millileters of 60% solution.____________________ Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! percent ---------------- quantity
Methanol Solution I 30 ---------------- x ml
Methanol Solution II 60 ------ 200 - x ml
Mixture 50 ---------------- 200
30 x + 60 ( 200 - x ) = 49.5 * 200
3000 x + 6000 ( 200 - x ) = 990000
3000 x + 1200000 - 6000 x = 990000
3000 x - 6000 x = 990000 - -1200000
-3000 x = -210000
/ -3000
x = 70 ml 30.00% Methanol Solution I 70ml
60.00% Methanol Solution II 130 ml
m.ananth@hotmail.ca
