SOLUTION: a chemist needed a 75% acid solution but only has 35% acid and 85% acid solutions. if he uses 120 ml of the 85% solution, how much of the 35% solution is needed to make the 75% sol
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Question 670910: a chemist needed a 75% acid solution but only has 35% acid and 85% acid solutions. if he uses 120 ml of the 85% solution, how much of the 35% solution is needed to make the 75% solution Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a chemist needed a 75% acid solution but only has 35% acid and 85% acid solutions. if he uses 120 ml of the 85% solution, how much of the 35% solution is needed to make the 75% solution
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Equations:
Quantity: x + y = 120 ml
Acid::: 35x+85y = 75*120
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35x + 35y = 35*120
35x + 85y = 75*120
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50y = 40(120)
y = (4/5)120
y = 96 ml (amt. of 85% solution needed)
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Solve for "x":
x + y = 120 ml
x + 96 = 120 ml
x = 24 ml (amt. of 35% solution needed)
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Cheers,
Stan H.
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