SOLUTION: completely factor: 16a^3 -2b^3

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Question 670774: completely factor: 16a^3 -2b^3
Answer by jim_thompson5910(35256) About Me  (Show Source):
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16a^3 -2b^3

2(8a^3 -b^3)

2((2a)^3 -b^3)

2((2a -b)((2a)^2 + (2a)*(b) + (b)^2) ... Use the difference of cubes factoring rule here

2(2a -b)(4a^2 + 2ab + b^2)

So 16a^3 -2b^3 completely factors to 2(2a -b)(4a^2 + 2ab + b^2)