SOLUTION: Two cars, each traveling at a constant rate, leave Boston headed for Philadelphia, 300 miles away. One car travels 10 miles per hour faster and arrives 1 hour earlier than the othe
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Question 670726: Two cars, each traveling at a constant rate, leave Boston headed for Philadelphia, 300 miles away. One car travels 10 miles per hour faster and arrives 1 hour earlier than the other car. Determine the rate of the faster car Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! D=RT
300=XT
T=300/X
AND:
300=(X+10)(T-1)
300=(X+10)[(300/X)-1]
300=300-X+3000/X-10
0=-X+3000/X-10 MULTIPLY BY -X.
X^2-3000+10X=0
X^2+10X-3000=0
(X-50)(X+60)=0
X-50=0
X=50 MPH. ANS.
300=50T
T=300/50
T=6 HOURS ANS.
300=(50+10)(6-1)
300=60*5 60 MPH. FOR 5 HOURS FOR THE FASTER CAR.
300=300
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