Question 67062: Al, Betty, and Claire, slipt $1000 among them to be invested in different ways. Each begins with a different amount. At the end of one year they have a total of $1500. Betty and Claire have both doubled their money, whereas Al had managed to lose $100. What was Al's original portion?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Al, Betty, and Claire, slipt $1000 among them to be invested in different ways. Each begins with a different amount. At the end of one year they have a total of $1500. Betty and Claire have both doubled their money, whereas Al had managed to lose $100. What was Al's original portion?
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Let A, B, C represent the original amts each had:
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"Al, Betty, and Claire, slipt $1000 among them" (Not sure what "slipt" means)
A + B + C = 1000
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AT the end of the year:
(A-100) + 2B + 2C = 1500
A + 2B + 2C = 1500 + 100
A + 2B + 2C = 1600
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They only want to know A (Al's portion) so eliminate B & C
A + B + C = 1000
A + 2B + 2C = 1600
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Mult the 1st equation by 2 and subtract:
2A + 2B + 2C = 2000
A + 2B + 2C = 1500
-----------------------Subtract
A + 0B + 0C = 500
A = $500 is Al's original amt.
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Make sense to you?
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