SOLUTION: how do I solve 4^(x-6)=16^x
I tried two methods, one where I change the base of 16 to 4^2 and solve from there, I got x=8
and then I tried the long method of making each one
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-> SOLUTION: how do I solve 4^(x-6)=16^x
I tried two methods, one where I change the base of 16 to 4^2 and solve from there, I got x=8
and then I tried the long method of making each one
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Question 670411: how do I solve 4^(x-6)=16^x
I tried two methods, one where I change the base of 16 to 4^2 and solve from there, I got x=8
and then I tried the long method of making each one a log but my answer came out to be x=-2
though my book says the answer should be -6...
thank you in advance for any help. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 4^(x-6)=16^x
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4^(x-6) = (4^2)^x
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4^(x-6) = 4^(2x)
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x-6 = 2x
x = -6
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Cheers,
Stan H.
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