You can put this solution on YOUR website! how to do these equations
(-4+3i)+(6-10i)
ADD/SUBTRACT IMAGINARY NUMBERS WITH 'I'S AND REAL NUMBERS WITHOUT 'I'S SEPARATELY
=(-4+6)+I(3-10)=2-7I
(1-4i)-(-3+5i)
=(1+3)+I(-4-5)=4-9I
(-2+3i)*(4-8i)
[-2*4]+[-2*(-8)+(3)(4)]I+(3)(-8)I^2..............I^2=-1...HENCE
[-8+24]+I[16+12]=16+28I
(-1+2i)/(-3+4i).........MULTIPLY AND DIVIDE WITH -3-4I
[(-1+2I)(-3-4I)]/[(-3+4I)(-3-4I)]
=(3-2I-8I^2)/(9-16I^2)
=(11-2I)/(25)