Question 670166: Bill, Mary, and Joe belong to a club of nineteen people. A committee of twelve is to be selected at random from the membership. How many different arrangements are possible? How many of these committees will contain Bill, Mary, and Joe at the same time?
For the first part, I got 19C12= 50,388
For the second part, I got 12C3= 220
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi,
Bill, Mary, and Joe belong to a club of nineteen people.
A committee of twelve is to be selected at random from the membership
How many different arrangements are possible? 19C12, Yes, good work
How many of these committees will contain Bill, Mary, and Joe at the same time?
might consider
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