SOLUTION: I tried this natural log problem and keep comming up with the wrong awnser of .25 HELP! (please) {{{2e^(3x)=4e^(5x)}}} Am i just bad at algebra or is this somewhat complicated

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I tried this natural log problem and keep comming up with the wrong awnser of .25 HELP! (please) {{{2e^(3x)=4e^(5x)}}} Am i just bad at algebra or is this somewhat complicated      Log On


   

Question 6701: I tried this natural log problem and keep comming up with the wrong awnser of .25 HELP! (please)
2e%5E%283x%29=4e%5E%285x%29 Am i just bad at algebra or is this somewhat complicated
Answer by ichudov(507) About Me  (Show Source):
You can put this solution on YOUR website!
great job on typing the formula.
2e%5E%283x%29=4e%5E%285x%29
2e%5E%283x%29%2F4e%5E%285x%29=1
%281%2F2%29%2Ae%5E%283x-5x%29=1
e%5E%28-2x%29=2
take natural log of both sides
-2x=ln%28+2+%29
x=-ln%28+2+%29%2F2