SOLUTION: at a school,2/5 of the students are taking chemistry, 1/3 of the remaining students are taking physics, and the rest are taking biology. no student is taking more than one science

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Question 670058: at a school,2/5 of the students are taking chemistry, 1/3 of the remaining students are taking physics, and the rest are taking biology. no student is taking more than one science class. if 66 students are taking biology, how many students are in the class?
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Let the total number of students = N

>>...2/5 of the students are taking chemistry,...<<
So 2%2F5N are taking chemistry

1/3 of the remaining students are taking physics,
The trick here is "the remaining students".  That is NOT 
1%2F3 of the total number of students!  It is only
1%2F3 of the students that remain after the 2%2F5N
chemistry students have been subtracted from N, which is 
N - 2%2F5N or 3%2F5N.  Therefore 1%2F3 of 3%2F5N 
is 1%2F5N.  So the number talking physics is 1%2F5N.

and the rest are taking biology. 

"The rest" is found by subtracting the 2%2F5N taking
chemistry and the 1%2F5N taking physics from N:

N - (2%2F5N + 1%2F5N) = N - 3%2F5N = 2%2F5%29%29%29N%0D%0A%0D%0Aso+%7B%7B%7B2%2F5N are taking biology 

>>...66 students are taking biology,...<<
So we set 2%2F5%29%29%29N+equal+to+66.+%0D%0A%0D%0A%7B%7B%7B2%2F5N = 66

Multiply through by 5

2N = 330
 N = 165

Edwin