SOLUTION: A pipe can fill a tank in 10 hours. If a second pipe is opened, the two pipes together can fill the tank in 6 hours. How long would it take the second pipe alone to fill the tank?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: A pipe can fill a tank in 10 hours. If a second pipe is opened, the two pipes together can fill the tank in 6 hours. How long would it take the second pipe alone to fill the tank?      Log On


   



Question 670005: A pipe can fill a tank in 10 hours. If a second pipe is opened, the two pipes together can fill the tank in 6 hours. How long would it take the second pipe alone to fill the tank?
Found 2 solutions by ewatrrr, josmiceli:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
A pipe can fill a tank in 10 hours.
If a second pipe is opened, the two pipes together can fill the tank in 6 hours.
How long highlight%28x%29would it take the second pipe alone to fill the tank?
Translate into an equation: PER hr KEY
+1%2F10+%2B+1%2Fx+=+1%2F6+ |Multiplying thru by 60x so as all denominators = 1
6x + 60 = 10x
60 = 4x
15hr = x

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Add their rates of filling to get rate
with both pipes open
1st pipe's rate:
( 1 tank ) / ( 10 hrs )
2nd pipe's rate:
( 1 tank ) / ( x hrs )
Both together:
( 1 tank ) / ( 6 hrs )
----------------
+1%2F10+%2B+1%2Fx+=+1%2F6+
Multiply both sides by +30x+
+3x+%2B+30+=+5x+
+2x+=+30+
+x+=+15+
The 2nd pipe alone can fill the tank in 15 hrs