SOLUTION: A pipe can fill a tank in 10 hours. If a second pipe is opened, the two pipes together can fill the tank in 6 hours. How long would it take the second pipe alone to fill the tank?
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: A pipe can fill a tank in 10 hours. If a second pipe is opened, the two pipes together can fill the tank in 6 hours. How long would it take the second pipe alone to fill the tank?
Log On
Question 670005: A pipe can fill a tank in 10 hours. If a second pipe is opened, the two pipes together can fill the tank in 6 hours. How long would it take the second pipe alone to fill the tank? Found 2 solutions by ewatrrr, josmiceli:Answer by ewatrrr(24785) (Show Source):
Hi,
A pipe can fill a tank in 10 hours.
If a second pipe is opened, the two pipes together can fill the tank in 6 hours.
How long would it take the second pipe alone to fill the tank?
Translate into an equation: PER hr KEY |Multiplying thru by 60x so as all denominators = 1
6x + 60 = 10x
60 = 4x
15hr = x
You can put this solution on YOUR website! Add their rates of filling to get rate
with both pipes open
1st pipe's rate:
( 1 tank ) / ( 10 hrs )
2nd pipe's rate:
( 1 tank ) / ( x hrs )
Both together:
( 1 tank ) / ( 6 hrs )
----------------
Multiply both sides by
The 2nd pipe alone can fill the tank in 15 hrs