SOLUTION: Please help me solve this equation - showing the steps - I am trying to help my daughter with some homework. Thank you, Peter y=(6x/5)-(x^2/50)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Please help me solve this equation - showing the steps - I am trying to help my daughter with some homework. Thank you, Peter y=(6x/5)-(x^2/50)      Log On


   



Question 669885: Please help me solve this equation - showing the steps - I am trying to help my daughter with some homework.
Thank you, Peter
y=(6x/5)-(x^2/50)

Found 3 solutions by mananth, ReadingBoosters, MathLover1:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
y=%286x%2F5%29-%28x%5E2%2F50%29
It is not clear to me what is to be done.since there are two variables x & y.
If you need to simplify then
y=%286x%2F5%29-%28x%5E2%2F50%29
LCD is 50
y=+%2810%2A6x-x%5E2%29%2F50
y=%2860x-x%5E2%29%2F50
m.ananth@hotmail.ca

Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
y = 6x%2F5 - x%5E2%2F50
...
0 = %286x%2F5%29%2810%2F10%29+-+x%5E2%2F50
0 = 60x%2F50+-+x%5E2%2F50
50(0) = 60x - x^2
0 = x(60 - x)
...
x = 0
...
-x + 60 = 0
-x = -60
x = 60
...
2 intercepts at (0,0) and (60,0)
...
graph%28300%2C200%2C-100%2C100%2C-100%2C100%2C%286x%2F5%29-%28x%5E2%2F50%29%29
.....................
Delighted to help.
-Reading Boosters
Wanting for others what we want for ourselves.
www.MyHomeworkAnswers.com

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
y=6x%2F5-x%5E2%2F50

y=%2810%2A6x%29%2F%2810%2A5%29-%28x%5E2%2F50%29

y=60x%2F50-x%5E2%2F50

y=%281%2F50%29%28-x%5E2%2B60x%29

write it in vertex form to find the coordinates of the vertex

y+=+a%28x-h%29%5E2+%2B+k

y=%281%2F50%29%28-x%5E2%2B60x%29%2B0...Complete the square, Take half of x coefficient and
square it. Notice to keep equation balanced you must add this number and
subtract it making the net effect zero.

y=%281%2F50%29%28-x%5E2%2B60x%2B900-900%29

y=%281%2F50%29%28%28x%5E2-30%29%5E2-900%29.....Distribute and add constants.

y=%281%2F50%29%28x%5E2-30%29%5E2-900%2F50

y=%281%2F50%29%28x%5E2-30%29%5E2-%28-18%29

y=%281%2F50%29%28x%5E2-30%29%5E2%2B18

so, h=30 and k=18 and vertex is at (30,18)
and parabola has a global maximum, it opens down