Question 669773: log(x^2+5x+16)=1
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! log (x^2 + 5x + 16) = 1
since log(a) = b if and only if 10^b = a, your equations can be changed to be:
10^1 = x^2 + 5x + 16 which becomes:
x^2 + 5x + 16 = 10
subtract 10 from both sides of the equation to get:
x^2 + 5x + 6 = 0
the roots of that equation are at:
x = -2
x = -3
to confirm, substitute these values into the original equations to see if the original equation holds true.
the original equation is:
log (x^2 + 5x + 16) = 1
when you substitute -2 for x and when you substitute -3 for x, the equation holds true confirming the solution is good.
the solution to the equation is:
x = -2 or x = -3
|
|
|
