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Question 669690: How to shade the solution set to the system of a inequalities.
x+2y>-2
3x+y<3
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! First solve for y in each equation and get into slope intercept form
x+2y>-2
2y > -x-2
y > -(1/2)x-2/2
y > -(1/2)x-1
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3x+y < 3
y < - 3x + 3
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So after solving for y, we get
y > -(1/2)x-1
y < - 3x + 3
Now graph the inequalities separately
To graph the inequality y > -(1/2)x-1, first graph the line y = -(1/2)x-1.
Make this line a dashed line.
Then shade above the dashed line.
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To graph the inequality y < - 3x + 3, first graph the line y = - 3x + 3.
Make this line a dashed line.
Then shade below the dashed line.
The final solution region will be the overlapping portion of the two individual shaded regions
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