SOLUTION: professor I'm having trouble understanding this problem. factor fx into linear factors given that k is a zero of fx.
Fx = 2x³-3x²-5x+6; k=1
the answer is: (x-1) (x-2) (2x+3)
b
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-> SOLUTION: professor I'm having trouble understanding this problem. factor fx into linear factors given that k is a zero of fx.
Fx = 2x³-3x²-5x+6; k=1
the answer is: (x-1) (x-2) (2x+3)
b
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Question 669276: professor I'm having trouble understanding this problem. factor fx into linear factors given that k is a zero of fx.
Fx = 2x³-3x²-5x+6; k=1
the answer is: (x-1) (x-2) (2x+3)
but I don't know how to get that answer. thanks! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! factor fx into linear factors given that k is a zero of fx.
Fx = 2x³-3x²-5x+6; k=1
the answer is: (x-1) (x-2) (2x+3)
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F(x) = 2x^3 -3x^2 -5x + 6
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Use synthetic division:
1)....2....-3....-5....6
......2....-1....-6...|..0
2)
......2....3....|..0
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Since x is a zero, x-1 is a factor:
Since 2 is a zero, x-2 is a factor:
Finally 2x+3 is a factor
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Cheers,
Stan H.
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