SOLUTION: find two consecutive odd integers such that one third of the smaller plus twice the larger equals 7 more than the sum of the two numbers. Explain your answer and show your work.
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Question 669131: find two consecutive odd integers such that one third of the smaller plus twice the larger equals 7 more than the sum of the two numbers. Explain your answer and show your work. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the odd integers be x & x+2
(1/3)x + 2(x+2)= x+x+2+7
x/3 + 2x+4 = 2x+9
multiply equation by 3
x+6x+12=6x+27
x= 27-12
x=15
The numbers are 15 & 17
