SOLUTION: What is a quartic function with only the two real zeros given? x = -4 and x = -1 A. y = x4 + 5x3 + 5x2 + 5x + 4 B. y = x4 - 5x3 - 5x2 - 5x - 4 C. y = -x4 + 5x3 + 5x2

Algebra ->  Equations -> SOLUTION: What is a quartic function with only the two real zeros given? x = -4 and x = -1 A. y = x4 + 5x3 + 5x2 + 5x + 4 B. y = x4 - 5x3 - 5x2 - 5x - 4 C. y = -x4 + 5x3 + 5x2       Log On


   

Question 669046: What is a quartic function with only the two real zeros given?
x = -4 and x = -1
A. y = x4 + 5x3 + 5x2 + 5x + 4
B. y = x4 - 5x3 - 5x2 - 5x - 4
C. y = -x4 + 5x3 + 5x2 + 5x + 4
D. y = x4 + 5x3 + 5x2 + 5x - 5
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
y+=+x%5E4+%2B+5x%5E3+%2B+5x%5E2+%2B+5x+%2B4......replace 5x%5E2 with x%5E2%2B4x%5E2
y+=x%5E4%2Bx%5E2%2B5x%5E3%2B5x%2B4x%5E2%2B4......group
y+=%28x%5E2%2B5x%2B4%29+%28x%5E2%2B1%29....replace 5x with 4x%2Bx+
y+=%28x%5E2%2B4x%2Bx%2B4%29+%28x%5E2%2B1%29.............group
y+=%28%28x%5E2%2B4x%29%2B%28x%2B4%29%29%28x%5E2%2B1%29
y+=%28x%28x%2B4%29%2B%28x%2B4%29%29%28x%5E2%2B1%29
y+=%28x%2B1%29%28x%2B4%29%28x%5E2%2B1%29
solutions:
%28x%2B1%29%28x%2B4%29+%28x%5E2%2B1%29=0
if %28x%2B1%29=0 the x=-1...real solution
if %28x%2B4%29=0 the x=-4..real solution

if %28x%5E2%2B1%29=0 the x%5E2=-1....=>...x=sqrt%28-1%29...=>...x=i and x=-i.....-complex solution-



so, your answer is A