SOLUTION: factor completely 6y^2-19y+15 Perform indicated operation & simplify and yes, this is all one problem 3x^2-20x-32 ___________ _ 2x^2-x-15 ___________ _

Algebra ->  Functions -> SOLUTION: factor completely 6y^2-19y+15 Perform indicated operation & simplify and yes, this is all one problem 3x^2-20x-32 ___________ _ 2x^2-x-15 ___________ _       Log On


   

Question 669043: factor completely
6y^2-19y+15

Perform indicated operation & simplify
and yes, this is all one problem
3x^2-20x-32
_____________
2x^2-x-15
_____________
9x^2+24x+16
_______________
2x^2+7x+5
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
factor completely
6y^2-19y+15
---
y = [19 +- sqrt(19^2 - 4*6*15)]/12
y = [19 +- sqrt(1)]/12
----
y = 20/12 or y = 18/12
y = 5/3 or y = 3/2
Factors: (3y-5)(2y-3)
========================
Perform indicated operation & simplify
and yes, this is all one problem
[(3x^2-20x-32)/(2x^2-x-15)] / [(9x^2+24x+16)/(2x^2+7x+5)]
=======================
[(3x+4)(x-8)/(2x-5)(x+3] / [(3x+4)(3x+4)/(2x+5)(x+1)]
-----
Cancel any factors that are common to a numerator and a denominator:
= [(x-8)/(2x-5)(x+3] / [(3x+4)/(2x+5)(x+1)]
-------
= [(x-8)(2x+5)(x+1)] / [(2x-5)(x+3)(3x+4)]
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Cheers,
Stan H.