SOLUTION: 1. Determine the slope and the y-intercept of the graph of the equation. 12x + y + 5 = 0 2. Use the given conditions to write an equation for the line in point-slope form.

Algebra ->  Linear-equations -> SOLUTION: 1. Determine the slope and the y-intercept of the graph of the equation. 12x + y + 5 = 0 2. Use the given conditions to write an equation for the line in point-slope form.       Log On


   

Question 668952: 1. Determine the slope and the y-intercept of the graph of the equation.
12x + y + 5 = 0
2. Use the given conditions to write an equation for the line in point-slope form.
Passing through (-2, -4) and (-6, -5)
3. Find the slope of the line that goes through the given points.
(-8, 5), (15, 1)
4.Use the given conditions to write an equation for the line in slope-intercept form.
Passing through (-2, -8) and (-8, -5)
5. Use the given conditions to write an equation for the line in point-slope form.
Slope = , passing through (5, 3)
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
1. 12x + y + 5 = 0
y = -12x - 5
slope is -12
y-intercept is -5
...
2. slope = %28-5--4%29%2F%28-6--2%29+=+-1%2F-4+=+1%2F4
y - -4 = 1%2F4(x- -2)
y + 4 = %281%2F4%29%28x%2B2%29
y+=+%281%2F4%29x+%2B+%281%2F4%29%282%29+-+4
y+=+%281%2F4%29x+%2B+%281%2F2%29+-+4
y+=+%281%2F4%29x+-+7%2F2
...
3. slope = %281-5%29%2F%2815--8%29+=+-4%2F23
...
4. slope = %28-5--8%29%2F%28-8--2%29+=+3%2F-6+=+-1%2F2
-8+=+%28-1%2F2%29-2+%2B+b
b = -8 - 1 = -9
y+=+%28-1%2F2%29x+-+9
...
5. slope?
y - 3 = m(x-5)
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