SOLUTION: Annual profit in thousands of dollars is given by the function, P(x) = -.1x2 + 50x - 300, where x is the number of items sold, x ≥ 0. I am suppose to explain -300? I beli

Algebra ->  Rational-functions -> SOLUTION: Annual profit in thousands of dollars is given by the function, P(x) = -.1x2 + 50x - 300, where x is the number of items sold, x ≥ 0. I am suppose to explain -300? I beli      Log On


   



Question 668949: Annual profit in thousands of dollars is given by the function, P(x) = -.1x2 + 50x - 300, where x is the number of items sold, x ≥ 0.
I am suppose to explain -300? I believe it has to do with the final costs, is this correct?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Annual profit in thousands of dollars is given by the function,
P(x) = -.1x2 + 50x - 300, where x is the number of items sold, x ≥ 0.
the -300 would be the adjustments to the annual profits due to 'fixed cost'
that is to say if NO items were sold..there would be a loss of $300,000
and...solving -1x^2 + 50x - 300 = 0 would tell us how many need to be sold
to break even.