SOLUTION: how do you graph the inequality y>2abolute value sign x+3 close absolute value sign -3

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Question 668891: how do you graph the inequality y>2abolute value sign x+3 close absolute value sign -3
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how do you graph the inequality y>2absolute value sign x+3 close absolute value sign -3
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Since the absolute value can never be negative it bottoms out
at x+3 = 0, or x = -3
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y = 2|x+3|-3
Plot a few points around x = -3, then draw the graph which is the boundary
for the inequality.
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If x = -6 y = 3
If x = -4 y = -1
If x = -2 y = -1
If x = -3 y = -3 (that is the bottom point
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Draw the v-shaped boundary by connecting those points.
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Since you want y to GREATER than the boundary shade the area
ABOVE the boundary.
Cheers,
Stan H.
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Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
y%3E2abs%28x%2B3%29-3
since the solution for abs%28x%2B3%29 is equal to x%2B3 or x%2B3, we have
y%3E2%28x%2B3%29-3
y%3E2x%2B6-3
y%3E2x%2B3.....set y=0 and solve for x
0%3E2x%2B3....=>....-3%3E2x.=>....-3%2F2%3Ex or x%3C-3%2F2=-1.5

or, if y%3E2%28-%28x%2B3%29%29-3
y%3E2%28-x-3%29-3
y%3E-2x-6-3
0%3E-2x-9
2x%3E-9
x%3E-9%2F2
x%3E-4.5


solution interval: y%3E2abs%28x%2B3%29-3 is defined for


+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+y%3E2abs%28x%2B3%29-3%29+