SOLUTION: equation for tangent function with a period of 3 pi/8 and phase shift of -pi/5

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Question 668834: equation for tangent function with a period of 3 pi/8 and phase shift of -pi/5
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
equation for tangent function with a period of 3 pi/8 and phase shift of -pi/5
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Equation for tan function: y=tan(Bx-C), Period=π/B, phase shift=C/B
For given problem:
period=3π/8=π/B
B=8/3
..
phase shift=-π/5=C/B=C/(8/3)=3C/8
-π/5=3C/8
C=-8π/15
..
Equation for given tan function: y=tan(8x/3+8π/15)