SOLUTION: 1. solve for x: 3b-8=10+(4-8b) 2. solve for x: x-3(1-x)=47-x 3. the greater of two numbers is 1 more than twice the smaller. three times the greater exceeds 5 times the small

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Question 668821: 1. solve for x: 3b-8=10+(4-8b)
2. solve for x: x-3(1-x)=47-x
3. the greater of two numbers is 1 more than twice the smaller. three times the greater exceeds 5 times the smaller by 10. find the numbers.
4. this month erica saved $20 more than last month. for the two months, she saved a total of $70. how much did she save each month?
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
1. Solve for b
3b - 8 = 10 + (4-8b)
Isolate b
3b + 8b = 10 + 4 + 8
11b = 22
highlight_green%28b+=+2%29
...
2. Solve for x
x-3(1-x)=47-x
Distribute the -3
x - 3 + 3x = 47 - x
Isolate x
x + 3x + x = 47 + 3
5x = 50
highlight_green%28x+=+10%29
...
3. x = 1+2y; 3x=5y+10
3(1+2y) = 5y + 10
3 + 6y = 5y + 10
6y - 5y = 10 - 3
highlight_green%28y+=+7%29
x=1+2(7) = highlight_green%28x+=+15%29
...
4. x = 20+y; x+y=70
20+y +y = 70
2y = 50
highlight_green%28y+=+25%29 last month
x = 20+25 = highlight_green%28x=45%29 this month
.....................
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