I'll assume you don't mean to use pennies or half dollars
then let q = the number of quarters
let d = the number of dimes
then 3d = the number of nickels.
Then there is a "coin equation" and a "money equation":
The "coin" equation is
+
+
= 85
The "money" equation is:
+
+
= $6.25
Simplify:
Simplify some more:
Multiply the second one through by 100 to clear of decimals:
Divide the second equation through by 25
Solve that and get q=5 and d=20
So there are 5 quarters, 20 dimes, and since there are 3d nickels,
there are 3(20) or 60 nickels.
--------------------
If you allow pennies there are two more solutions:
12 quarters, 12 dimes, 36 nickels and 25 pennies
19 quarters, 4 dimes, 12 nickels and 50 pennies.
But there are no solutions using half dollars.
Edwin