SOLUTION: say there are 5 male undergraduates, 2 female undergrduates, 2 male graduates, and 2 female graduates. find the probability of selecting an undergraduate or a female? i thought it

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Question 668477: say there are 5 male undergraduates, 2 female undergrduates, 2 male graduates, and 2 female graduates. find the probability of selecting an undergraduate or a female? i thought it was (7+4)/11 but thats just one ...
Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
say there are 5 male undergraduates, 2 female undergrduates, 2 male graduates, and 2 female graduates. find the probability of selecting an undergraduate or a female? i thought it was (7+4)/11 but thats just one ...
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P(undergrad OR female) = P(undergrad) + P(female) - P(undergrad AND female)
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= [7 + 4 - 2]/11 = 9/11
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Cheers,
Stan H.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
say there are 5 male undergraduates, 2 female undergrduates, 2 male graduates, and 2 female graduates. find the probability of selecting an undergraduate or a female? i thought it was (7+4)/11 but thats just one ...
Your error is because when you add the 7 undergraduates and the 4
females you are counting the 2 undergraduate females TWICE!  You are
counting them once among the 7 undergraduates and again among the
4 females.  Therefore you have to subtract those 2 once from the 7+4
to keep from counting them twice. Therefore you get %287%2B4-2%29%2F11 = 9%2F11.

You can also make a chart:

       -------------------------------------------
       |   grad   |  undergraduate   ||  totals  |
--------------------------------------------------
male   |    2     |       5          ||    7     |
--------------------------------------------------
female |    2     |       2          ||    4     |
==================================================
totals |    4     |       7          ||   11     |

You only want to count the red numbers which add up to 9,
So the probability is 9%2F11

Or you can use the formula that the other tutor used:

P(U or F) = P(U) + P(F) - P(U and F)
          = 7%2F11 + 4%2F11 - 2%2F11
          = 9%2F11

Edwin