Question 668278: x+3y=18
3x-4y=2
Answer by gwendolyn(128)   (Show Source):
You can put this solution on YOUR website! x+3y=18
3x-4y=2
First, let's isolate x in the first equation by subtracting 3y from both sides:
x+3y=18
x=18-3y
Then, we can plug in this value of x into the second equation:
3x-4y=2
3(18-3y)-4y=2
Now we can distribute the 3 to the value in parentheses:
54-9y-4y=2
Next, we combine like terms (the constants and the y values):
54-13y=2
52-13y=0
52=13y
To get the value of y, all we have to do is divide by 13:
4=y
And then we can plug this value into the first equation to find x:
x+3y=18
x+3*4=18
x+12=18
x=6
Finally, let's check these values by plugging them into the second equation:
3x-4y=2
3*6-4*4=2
18-16=2
2=2
This equation checks, so we know that y=4 and x=6.
|
|
|
