SOLUTION: The length of a rectangle is 3 meters more than twice its width. The perimeter is 48 meters. Let w represent the width. Find the length and width of the rectangle.

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Question 668028: The length of a rectangle is 3 meters more than twice its width. The perimeter is 48 meters. Let w represent the width. Find the length and width of the rectangle.
Answer by Adrianne15(25) About Me  (Show Source):
You can put this solution on YOUR website!
Let W represent the width of the rectangle. Let the length of the rectangle be (2W+3).
2L%2B2W=P Formula for perimeter (sort-of)
2%282W%2B3%29%2B2W=48 (substitute)
4W%2B6%2B2W=48 (simplify/expand)
6W=48-6 (isolate x)
6W=42
W=7
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Now substitute W into the length expression to find the length.
L=2W%2B3
2%287%29%2B3
14%2B3
17
Therefore, the length of the rectangle is 17 meters, and the width is 7 meters.