SOLUTION: What weight of water must be added to 50 lb of a 36% sulfuric acid solution to yield a 20% solution? All percentage are by weight. please help me....

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Question 667811: What weight of water must be added to 50 lb of a 36% sulfuric acid solution to yield a 20% solution? All percentage are by weight.
please help me....
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

What weighthighlight%28x%29 of water must be added to 50 lb of a 36% sulfuric acid solution 

to yield a 20% solution? 

          WATER = WATER ( and...lbs the same on both sides of the EQ)

  x + .64*50lb = .80(50lb+x)

     .2x = .16*50lb

        x = 40lb of water must be added

and...

 40lb+%2B+32lb+=+72+lb+=+.80%2A+90lb