SOLUTION: This is my question.
The product of two consecutive even integers is 56. Find the two integers.
I got this far
x(x+2)= 56
x^+2x= 56
x^+2x-56 = 0
(x-?)(x+?)= 0
thanks
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-> SOLUTION: This is my question.
The product of two consecutive even integers is 56. Find the two integers.
I got this far
x(x+2)= 56
x^+2x= 56
x^+2x-56 = 0
(x-?)(x+?)= 0
thanks
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Question 6677: This is my question.
The product of two consecutive even integers is 56. Find the two integers.
I got this far
x(x+2)= 56
x^+2x= 56
x^+2x-56 = 0
(x-?)(x+?)= 0
thanks Found 2 solutions by xcentaur, ichudov:Answer by xcentaur(357) (Show Source):
Quadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=228 is greater than zero. That means that there are two solutions: .
Quadratic expression can be factored:
Again, the answer is: 6.54983443527075, -8.54983443527075.
Here's your graph:
the answer to this equation is not integer.
so, the answer is that there is no answer to your problem. It is a trick problem.
Think about it, product of consecutive integers 6 and 8 is 48, and for the next two consecutive integers (8 and 10) it is 80.