SOLUTION: Solve for x: log(3x+8) - log(x-2) =1
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Question 667600
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Solve for x: log(3x+8) - log(x-2) =1
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solver91311(24713)
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The difference of the logs is the log of the quotient.
Use the definition of the logarithm function and the convention that an unspecified base is assumed to be base 10.
Solve for
John
My calculator said it, I believe it, that settles it