SOLUTION: Sprinter A runs 100 meters in 15 seconds, while sprinter B starts 1.5 seconds later and runs 100 meters in 14 seconds. If each of them runs at a constant rate, who is further in 10

Algebra ->  Expressions-with-variables -> SOLUTION: Sprinter A runs 100 meters in 15 seconds, while sprinter B starts 1.5 seconds later and runs 100 meters in 14 seconds. If each of them runs at a constant rate, who is further in 10      Log On


   



Question 667399: Sprinter A runs 100 meters in 15 seconds, while sprinter B starts 1.5 seconds later and runs 100 meters in 14 seconds. If each of them runs at a constant rate, who is further in 10 seconds after the start of the race? Explain.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Sprinter A runs 100 meters in 15 seconds,
while sprinter B starts 1.5 seconds later and runs 100 meters in 14 seconds.
If each of them runs at a constant rate, who is further in 10 seconds after the start of the race? Explain.
:
Find the distance run by A in 10 sec: 10%2F15 * 100 = 66.67 meters
:
Sprinter B started 1.5 sec later, find his dist: 8.5%2F14 * 100 = 60.7 meters