SOLUTION: 2^(4y+1)-3^y=0

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Question 667191: 2^(4y+1)-3^y=0
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2^(4y+1)-3^y=0
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2%5E%284y%2B1%29+=+3%5Ey
(4y+1)log(2) = y*log(3)
4y*log(2) + log(2) = y*log(3)
4y*log(2) - y*log(3) = -log(2)
y*log(16) - y*log(3) = - log(2)
y*(log(16) - log(3) = -log(2)
y+=+log%282%29%2F%28log%283%29+-+log%2816%29%29
y+=+log%282%29%2Flog%283%2F16%29
=~ -0.41407