SOLUTION: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46.

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Question 66701: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Try this!
Let n be the first integer, then n+1 is the next consecutive integer. From the problem description, you can write:
2n+%2B+4%28n%2B1%29+=+46 Simplify and solve for n.
2n+%2B+4n+%2B+4+=+46 Combine like-terms.
6n+%2B+4+=+46 Subtract 4 from each side.
6n+=+42 Divide both sides by 6.
n+=+7 This is the first integer.
n%2B1+=+8 This is the next consecutive integer.
Check:
2(7) + 4(8) = 14 + 32 = 46 OK!