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Question 66668: Please help to solve
square root of x + 2 = the square root of x +12
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! square root of x + 2 = the square root of x +12
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The use of brackets would sure help here, to let us know just exactly what the problems is.
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I am going to assume you mean:
SqRt(x) + 2 = SqRt(x + 12)
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[SqRt(x)+2]^2 = [SqRt(x+12)]^2; square both sides
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FOIL [SqRt(x)+ 2] [SqRt(x)+ 2] and you have:
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x + 4SqRt(x) + 4 = x + 12
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Get the radical on the left by itself:
4*SqRt(x) = x + 12 - x - 4
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4*SqRt(x) = +8
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Square both sides again:
16(x) = 64
x = 64/16
x = 4
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you can check this, substitute 4 x in the original equation:
SqRt(4) + 2 = SqRt(4 + 12)
2 + 2 = SqRt(16)
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If this problem was different from what I assumed, email me and we will see what we can do with it.
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