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Question 666400: find the slope and y intercept of the line y=4
find an equation of a line satisfying the given coditions
perpendicular to x=7, passing through (-5,4)
Answer by DrBeeee(684)   (Show Source):
You can put this solution on YOUR website! The slope-intercept form of a line is
(1) y = m*x + b, where m, the coefficient of x, is equal to the slope, and b is where the line crosses the y-axis, called the y intercept.
The equation of your line is
(2) y = 4
Writing your line in the form of (1) we get
(3) y = 0*x + 4, where I show that the coefficient of x is zero because you do not have an x-term. Comparing (3) to (1) we have m = 0, which means that the slope of your line, which is equal to m, is ZERO. It is a line parallel to the x-axis that crosses the y-axis at y = 4. Thus the y-intercept of your line, equal to b, is 4.
Your second line is a vertical line, parallel to the y-axis, crossing the x-axis at x = 7. A line perpendicular to a vertical line is a horizontal line (just like your first one). As such it has a slope equal to 0. Since it must go through the point (-5,4), you tell me what the y-intercept is! You're right it is 4. This line is the same as your first line
(4) y = 0*x + 4 or
(5) y = 4
Note that the horizontal line y = 4 does not depend on the value of x, y is always 4 no matter what x is. You would get the same answer if the line had to go through the point (any number,4)
I hope I didn't confuse you. Good luck in seeing the big picture of what a line is. It's really not too hard, hang in there.
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