SOLUTION: Given 2x+3y=8 and 4x-Ky=12, find the value for K so that 1. The lines will be parallel 2. The lines will be perpendicular

Algebra ->  Linear-equations -> SOLUTION: Given 2x+3y=8 and 4x-Ky=12, find the value for K so that 1. The lines will be parallel 2. The lines will be perpendicular      Log On


   

Question 666292: Given 2x+3y=8 and 4x-Ky=12, find the value for K so that
1. The lines will be parallel
2. The lines will be perpendicular
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
2x + 3y = 8
3y = -2x + 8
y = -2%2F3x + 8%2F3
Slope is -2%2F3
...
4x - Ky = 12
Ky = 4x - 12
y = 4%2FKx - 12%2FK
...
Parallel line
4%2FK+=+-2%2F3
cross multiply
4(3) = K(-2)
12 = -2K
highlight_green%28K+=+-6%29 in a parallel line
...
Perpendicular line
4%2FK+=+3%2F2
cross multiply
4(2) = K(3)
8 = 3K
highlight_green%28K+=+8%2F3%29 in a perpendicular line
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