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Question 666113:  Find 3 consecutive even numbers such that the sum of twice the first number and the third number is 30 more than the second number 
 Answer by swincher4391(1107)      (Show Source): 
You can  put this solution on YOUR website! Let x be the first number. 
Similarly, x+2 and x+4 are the next consecutive even numbers.
 
Sum of twice the first number and the third number is 30 more than the second would be:
 
2(x) + x+4 = x+2 + 30
 
 
2x + x + 4 = x + 32
 
3x + 4 = x + 32
 
2x = 28
 
x = 14
 
So, the numbers are 14,16,18. 
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