|  | 
| 
 
 
| Question 666113:  Find 3 consecutive even numbers such that the sum of twice the first number and the third number is 30 more than the second number
 Answer by swincher4391(1107)
      (Show Source): 
You can put this solution on YOUR website! Let x be the first number. Similarly, x+2 and x+4 are the next consecutive even numbers.
 Sum of twice the first number and the third number is 30 more than the second would be:
 2(x) + x+4 = x+2 + 30
 
 2x + x + 4 = x + 32
 3x + 4 = x + 32
 2x = 28
 x = 14
 So, the numbers are 14,16,18.
 | 
  
 | 
 |  |  |