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Question 666113: Find 3 consecutive even numbers such that the sum of twice the first number and the third number is 30 more than the second number
Answer by swincher4391(1107) (Show Source):
You can put this solution on YOUR website! Let x be the first number.
Similarly, x+2 and x+4 are the next consecutive even numbers.
Sum of twice the first number and the third number is 30 more than the second would be:
2(x) + x+4 = x+2 + 30
2x + x + 4 = x + 32
3x + 4 = x + 32
2x = 28
x = 14
So, the numbers are 14,16,18.
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