SOLUTION: the length of a rectangle is 5 in more than its width the perimeter of the recatngle is 42 in what is the length of the rectangle?

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Question 665422: the length of a rectangle is 5 in more than its width the perimeter of the recatngle is 42 in what is the length of the rectangle?
Found 2 solutions by bloggauta, ReadingBoosters:
Answer by bloggauta(8) About Me  (Show Source):
You can put this solution on YOUR website!
P= 2w+2L= 2w+2(w+5)
P= 4w+10= 42 => w= 32/4 then w= 8in and L= 13in

Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
Given
l = w+5
p = 42
...
Known
p = 2l+2w
...
Substitute l into the equation for p
42 = 2(w+5) + 2w
Distribute the 2
42 = 2w+ 10 + 2w
Combine like terms
42 = 4w + 10
Isolate w
4w = 32
Divide both sides by 4
w = 8 in
l = 8+5=13 in
...
Check

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