Question 664992: In the game of blackjack as played in casinos, the dealer has the advantage as most of the players do not play very well. As a result, the probability that the average player wins a hand is about 40%. An average player decides to play 10 hands. e. Assuming that this player has already lost the first 6 hands, what is the probability that he will win all remaining (4) hands?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! ): In the game of blackjack as played in casinos, the dealer has the advantage as most of the players do not play very well. As a result, the probability that the average player wins a hand is about 40%. An average player decides to play 10 hands. e. Assuming that this player has already lost the first 6 hands, what is the probability that he will win all remaining (4) hands?
-----
The results on each hand are independent.
---
P(win 4 hands) = 0.4^4 = 0.0256
=======================
Cheers,
Stan H.
|
|
|
