Question 66475This question is from textbook Algebra 1
: A private airplane leaves an airport and flies due south at 192 km/h. Two hours later a jet leaves the same airport and flies due south at 960 km/h. When will the jet overtake the plane?
THANK YOU!
This question is from textbook Algebra 1
Answer by ptaylor(2198)   (Show Source):
You can put this solution on YOUR website! A private airplane leaves an airport and flies due south at 192 km/h. Two hours later a jet leaves the same airport and flies due south at 960 km/h. When will the jet overtake the plane?
THANK YOU!
distance (d)=rate (r) times Time (t)
d=rt
Let t=time it takes for the jet to catch the private plane
Now we are told that when the jet leaves, the private plane has already been flying for two hours. Therefore, the private plane has already traveled a distance of (192km/h)(2h)=384 km
(960)(t)= distance travelled by the jet when the private plane is overtaken
384+(192)(t)=distance travelled by the private plane with it is overtaken
When these two distances are equal, the private plane will be overtaken. So our equation to solve is:
960t=384+192t subtract 192t from both sides:
960t-192t=384
768t=384
t=.5h=.5(60)m
t=30 minutes after the jet takes off, it will overtake the private plane
ck
(960)(.5)=384+192(.5)
480=384+96
480=480
Hope this helps----ptaylor
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