SOLUTION: What is the maximum volume of a open box created from a square of side length 24? Keep in mind that V=LWH. So for this problem the dimensions are as follows: L = 24-2x, W = 24-2x

Algebra ->  Trigonometry-basics -> SOLUTION: What is the maximum volume of a open box created from a square of side length 24? Keep in mind that V=LWH. So for this problem the dimensions are as follows: L = 24-2x, W = 24-2x      Log On


   



Question 664592: What is the maximum volume of a open box created from a square of side length 24? Keep in mind that V=LWH. So for this problem the dimensions are as follows:
L = 24-2x, W = 24-2x and H = x. The maximum volume will be where the volume equation is the greatest.
You are to determine:
1. The volume equation.
2. The maximum volume.
3. The value of x that maximizes the volume.
Explain each step.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Multiply length times width times height:



So



Take the first derivative (Power and Sum Rules)



Set the first derivative equal to zero and solve. This is a quadratic so you will get two roots, each of which represents the abscissa of a local extremum of the original function.

Take the second derivative:



Evaluate



where is either of the abscissas of the possible extreme points. If then is the abscissa of a local maximum, if then is the abscissa of a local minimum. If , the second derivative test is inconclusive, but it is a possible inflection point. In the latter case, for this problem, calculate the volume for the value of in question and see if it makes sense as a possible value that could give a maximum volume.

John

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