SOLUTION: Dear Sir/Madam, I am confronted with the following problem: "Solve the inequality: {{{ -5/(7-2x) >= 0 }}}" Can you explain to me why {{{ x = 7/2 }}} would not be a s

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Dear Sir/Madam, I am confronted with the following problem: "Solve the inequality: {{{ -5/(7-2x) >= 0 }}}" Can you explain to me why {{{ x = 7/2 }}} would not be a s      Log On


   



Question 6645: Dear Sir/Madam,
I am confronted with the following problem:
"Solve the inequality:
+-5%2F%287-2x%29+%3E=+0+"
Can you explain to me why +x+=+7%2F2+ would not be a solution?
Thanks in advance.
Regards,
-Mike

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Because denominators can NEVER equal ZERO--not in this lifetime, and probably not in the one to come!! If x+=+7%2F2, then the denominator will be zero, which is not allowed in any problem!!

R^2 at SCC