SOLUTION: Dear Sir/Madam,
I am confronted with the following problem:
"Find the center and radius of the circle with the following equation:
x^2 + y^2 - 10x + 8y -40 = 0"
I have
Algebra ->
Coordinate Systems and Linear Equations
-> SOLUTION: Dear Sir/Madam,
I am confronted with the following problem:
"Find the center and radius of the circle with the following equation:
x^2 + y^2 - 10x + 8y -40 = 0"
I have
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Question 6644: Dear Sir/Madam,
I am confronted with the following problem:
"Find the center and radius of the circle with the following equation:
x^2 + y^2 - 10x + 8y -40 = 0"
I have absolutely no idea how to approach this question. I want to use the x^2 + y^2 = r^2 formula, but I don't how to integrate that into this problem. Can you please help me?
Thanks in advance.
Regards,
-Mike Answer by rapaljer(4671) (Show Source):
Get the x terms together, and the y terms together, and leave a space after each to complete the square. Also add + 40 to each side of the equation:
For the first blank, take half of the 10, which is 5 and square to get 25.
For the second blank, take half of the 8, which is 4 and square to get 16. Add these to both sides of the equation:
Therefore this is a circle whose center is at (5, -4) and so .