SOLUTION: mr. west drove his car from home to chicago at the rate of 40 mph. amd returned at a rate of 45mph. if his time going exceed his time returning by 30 minutes, find his time going a
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-> SOLUTION: mr. west drove his car from home to chicago at the rate of 40 mph. amd returned at a rate of 45mph. if his time going exceed his time returning by 30 minutes, find his time going a
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Question 6642: mr. west drove his car from home to chicago at the rate of 40 mph. amd returned at a rate of 45mph. if his time going exceed his time returning by 30 minutes, find his time going and his time returning Answer by prince_abubu(198) (Show Source):
You can put this solution on YOUR website! We're going to use rate * time = distance in this situation. Before we go on, we must keep in mind that the distance for both to and from trips is the same.
Let's nail down the trip home first.
= Rate going back home = 45 mph. = We don't know yet.
Distance from Chicago to home would then be .
Let's nail down the trip to Chicago then.
= Rate to Chicago = 40 mph = time it took to go to Chicago = <----- We said 0.5 hours (instead of saying + 30) because the speed is in miles per hour.
Distance from home to Chicago would have to be .
Since the rates and times HAVE TO equal the same distance, we can set them equal to each other.
<---- used distributive property
<---- subtracted from both sides.
<---- Took him four hours to get home from Chicago. If his trip to Chicago took 30 minutes longer, then his trip to Chicago took 4.5 hours.