Question 664134: What is the center (or vertex if it is a parabola) of y^2+4x=8?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! What is the center (or vertex if it is a parabola) of y^2+4x=8?
y^2+4x=8
y^2=-4x+8
y^2=-4(x+2)
This is an equation of a parabola of the form:
(y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex.
For this problem: vertex is at (0,-2)
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