SOLUTION: solve the quadratic equation using the quadratic formula 6x2 + 12x +3 =0

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Question 664111: solve the quadratic equation using the quadratic formula
6x2 + 12x +3 =0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29

x+=+%28-%2812%29%2B-sqrt%28%2812%29%5E2-4%286%29%283%29%29%29%2F%282%286%29%29

x+=+%28-12%2B-sqrt%28144-%2872%29%29%29%2F%2812%29

x+=+%28-12%2B-sqrt%2872%29%29%2F12

x+=+%28-12%2Bsqrt%2872%29%29%2F12 or x+=+%28-12-sqrt%2872%29%29%2F12

x+=+%28-12%2B6%2Asqrt%282%29%29%2F12 or x+=+%28-12-6%2Asqrt%282%29%29%2F12

x+=+%28-2%2Bsqrt%282%29%29%2F2 or x+=+%28-2-sqrt%282%29%29%2F2

x+=+-0.292893 or x+=+-1.707107

So the exact solutions are x+=+%28-2%2Bsqrt%282%29%29%2F2 or x+=+%28-2-sqrt%282%29%29%2F2

and the approximate solutions are x+=+-0.292893 or x+=+-1.707107