SOLUTION: Pure acid is to be added to a 5% acid solution to obtain 95L of 28% solution. What amounts of each should be used? How many liters should be used of 100% pure acid to make this sol
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Question 663713: Pure acid is to be added to a 5% acid solution to obtain 95L of 28% solution. What amounts of each should be used? How many liters should be used of 100% pure acid to make this solution? Answer by ewatrrr(24785) (Show Source):
Hi, Pure acid is to be added to a 5% acid solution to obtain 95L of 28% solution.
Algebraically Question states*** acid = acid
x = 23L, amount of pure acid to add to 72L of the 5% solution
and... = 26.6L of acid are involved
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